# Line slope calculator 10x-y=30

**Straight line given by points A[3; 0] and B[4; 10]**

## Calculation:

**Slope-intercept form of line:**y = 10x-30

**Canonical form of the line equation:**10x-y-30 = 0

**Parametric form of the line equation:**

x = t+3

y = 10t ; t ∈ R

**Slope:**m = 10

**Slope angle of line: φ =**84°17'22″ = 1.4711 rad

**X intercept:**x

_{0}= 3

**Y intercept:**y

_{0}= q = -30

**Distance line from the origin:**d

_{0}= 2.9851

**The length of the segment AB: |AB| =**10.0499

**Vector: AB =**(1; 10)

**Normal vector: n =**(10; -1)

**Midpoint of the segment AB: M =**[3.5; 5]

**Perpendicular Bisector equation:**x+10y-53.5 = 0

**Vector OA = (3; 0) ; |OA| = 3**

**Vector OB = (4; 10) ; |OB| = 10.7703**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 68°11'55″ = 1.1903 rad**